Oblicz liczbę moli HNO3 potrzebną do zobojętnienia 29 g Mg (OH)2
2HNO₃ + Mg(OH)₂ - Mg(NO₃)₂ + 2H₂O
mHNO₃ = 48 + 15 = 63 g/mol
mMg(OH)₂ = 24 + 34 = 58g/ mol
126 g HNO₃ - 58g Mg(OH)₂
x g HNO₃ - 29g Mg(OH)₂
x = 63 g HNO₃
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2HNO₃ + Mg(OH)₂ - Mg(NO₃)₂ + 2H₂O
mHNO₃ = 48 + 15 = 63 g/mol
mMg(OH)₂ = 24 + 34 = 58g/ mol
126 g HNO₃ - 58g Mg(OH)₂
x g HNO₃ - 29g Mg(OH)₂
x = 63 g HNO₃