Oblicz liczbę moli dla 80g azotu cząsteczkowego
M(N2)=2*14g/mol=28g/mol
28g----------------1mol
80g----------------xmol
x=80g*1mol/28g
x=2,9mol
mN2= 28g/mol 1mol--- 28g x moli --- 80g
x= 80moli/28 = 2,86moli Pozdrawiam, kate66 ;)
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M(N2)=2*14g/mol=28g/mol
28g----------------1mol
80g----------------xmol
x=80g*1mol/28g
x=2,9mol
mN2= 28g/mol
1mol--- 28g
x moli --- 80g
x= 80moli/28 = 2,86moli
Pozdrawiam, kate66 ;)