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g=10m/s2 F=m*g
m=60kg
s=2*10cm2=20cm2=0,002m2
F=60kg*10m/s2=600N
p=600N/0,002m2=300000Pa=3000hPa
Odp:. Ciśnienie wywierane przez łyżwiarza to 3000hPa.