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mH2SO3=82u
%mS = 32u*100%/82u=39%
w siarkowym(VI)
mH2SO4=98u
%mS= 32u*100%/98u=32,65%
mS - 32u
100% - 82u
x% - 32u
x=(100%*32u)/82u=39,02%
mH2SO4 - 2*1u+32u+4*16u=98u
mS - 32u
100% - 98u
x% - 32u
x=(100%*32u)/98u=32,65%