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mO2=16g
nO2=16/32=0,5mola
1mol O2 -22,4dm3
0,5 mola -x
x=11,2dm3O2
x --- 16g
x=0,5mol
warunki normalne
1mol gazu ---22,4dm³
0,5molgazu---- y
y=11,2dm³
odpowiedz 16g tlenu w war norm zajmuje 11,2dm³