oblicz jaką liczbę moli stanowi
a) 10 g magnezu
b) 1 gram sodu
c)10 ton węgla
a)
m=10 g
M (Mg)=24 g/mol
n=m/M
n=10/24=0,42 mol
b)
m=1 g
M (Na)=23 g/mol
n=1/23=0,0435 mol
c)
m=10 t=10000 kg=10000000 g
M (C)=12 g/mol
n=10000000/12=833333,33 mol
24g magnezu - 1 mol
10g magnezu - x
24x=10
x=0,42 mola
23g sodu - 1 mol
1g sodu - x
23x=1
x=0,043 mola
12g węgla - 1mol
10000000g węgla - x
12x=10000000
x=833333,3 mola
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
a)
m=10 g
M (Mg)=24 g/mol
n=m/M
n=10/24=0,42 mol
b)
m=1 g
M (Na)=23 g/mol
n=1/23=0,0435 mol
c)
m=10 t=10000 kg=10000000 g
M (C)=12 g/mol
n=10000000/12=833333,33 mol
a)
24g magnezu - 1 mol
10g magnezu - x
24x=10
x=0,42 mola
b)
23g sodu - 1 mol
1g sodu - x
23x=1
x=0,043 mola
c)
12g węgla - 1mol
10000000g węgla - x
12x=10000000
x=833333,3 mola