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a) m = 36 g
M h2o = 2 + 16= 18 g/mol
n = 36/18 = 2 mole
b) m = 12 g
Mh2 = 2 g/mol
n = 12/2 = 6 moli
c) m = 3,2 g
MO2 = 32 g/mol
n = 3,2/32 = 0,1 mola
18 g - 1 mol
36 g - x
x=2 mole
MH₂=2 g/mol
2 g - 1 mol
12 g - x
x=6 moli
MO₂=32 g/mol
32 g - 1 mol
3,2 - x
x=0,1 mola
n- liczba moli
M-masa molowa
m- masa w gramach
a) 36 gram wody
M(H2O)= 18g/mol
n=36/18=2 [mole]
b) 12 gram wodoru cząsteczkowego
M(H2)=2g/mol
n=12/2=6 [moli]
c) 3,2 gram tlenu cząsteczkowego
M(O2)=32g/mol
n=3.2/32=0.1 [moli]