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T₁ = 10⁰C
m₂ = 5l
T₂ = 60⁰C
T₃ = 30⁰C
Szukane:
m₁ = ?
m₁ = (m₂T₂ - m₂T₃)/T₃ - T₁[l*⁰C/⁰C = l]
m₁ = 5l*60⁰C -5l*30⁰C/30⁰C-10⁰C
m₁ = 300l * ⁰C - 150l * ⁰C/20⁰C
m₁ = 150l * ⁰C/20⁰C
m₁ = 7,5l
odp. Do 5l. wody o temperaturze 60⁰C należy wlać 7,5l. wody o temperaturze 10⁰C aby temperatura wody wynosiła 30⁰C.