Oblicz ile wody nalezy dodac do 1kg 30% roztworu aby otrzymać roztwor 10%
Cp=ms/mr*100%
30%=ms/1000g*100%
0,3=ms/1000
ms=300g
0,1=300/(1000+x)
100+0,1x=300
0,1x=200
x=2000g=2kg wody należy dolac
1kg 30%......................10 - 0 = 10
.................10%
xkg O%......................30 - 10 = 20
1/x = 10/20
10x = 20
x = 2kg wody
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Cp=ms/mr*100%
30%=ms/1000g*100%
0,3=ms/1000
ms=300g
0,1=300/(1000+x)
100+0,1x=300
0,1x=200
x=2000g=2kg wody należy dolac
1kg 30%......................10 - 0 = 10
.................10%
xkg O%......................30 - 10 = 20
1/x = 10/20
10x = 20
x = 2kg wody