Oblicz ile trzeba odważyć siarki,aby próbka zawierała tyle atomow ile jest ich w 3,5g żelaza
3,5 g Fe - x at.
56 g Fe - 6,02*10^23 at
x = 0,38*10 ^23 at
0,38*10^23 at - x g S
6,02*10^23 at - 32 g S
x = 2 g S
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3,5 g Fe - x at.
56 g Fe - 6,02*10^23 at
x = 0,38*10 ^23 at
0,38*10^23 at - x g S
6,02*10^23 at - 32 g S
x = 2 g S