Oblicz ile poszczególnych pierwiastków zawierają związki : a)2*C6H12O6
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m związku=2*(6*12u+12*1u+6*16u)=360
mC=(12u*6)*2=144u
%C=144/360*100%=40%
mH=(12*1u)*2=24u
%H=24/360*100%=6 2/3%
mO=(6*16u)*2=192u
%O=192/360*100%=53 1/3%