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2B + N2 --> 2BN a więc 1 mol azotu twory 2 mole azotku, a objętość 1 mola azotu to 22,4 dm3, zatem:
22,4 dm3 - 2 mole
2,8 dm3 - x
x = 0,25 mola - tyle powstanie azotku boru.