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mAl2S3=?
mAl=108g
MmolAl=27g/mol
MmolAl2S3=150g/mol
z proporcji:
2*27g Al ------ 150g Al2S3
108g Al-----x Al2S3
x=300g Al2S3
Odp.Powstanie 300g siarczku glinu.