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mr1=150g
Cp1=40%
Cp2=25%
obliczamy ms1:
40gs --- 100g r-ru
x gs --- 150g r-ru
x=60g s
mH2O1=mr1-ms1=150g-60g=90g
ms1=ms2
obliczmy mH2O2
25gs --- 75g H2O
60gs --- x
x=180g H2O
mH2Odod.=mH2O2-mH2O1=180g-90g=90g
Odp.Należy dodac 90 g wody aby otrzymac 25% roztwór.