Oblicz, ile gramów tlenu przereaguje z 20 gramami wodoru z utworzeniem wody?Proszę na teraz !!!
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Odpowiedź:
mH2 = 20g
2H2 + O2 + 2H2O
mH = 1g, mO = 16g
2 * 1g = 2g wodoru
2 * 16g = 32g tlenu
2g * 2 H2 --- 32g O2
20g H2 --- x O2
x = 20g * 32g / 4g = 160g tlenu