Oblicz ile gramów tlenu należy użyć do utlenienia 15 gramów glinu.
4Al+3O2----->2Al2O3
15g x
2mAl=4*27u=108u
6mO=6*16u=96u
108u-------15g
96u---------x
x=13,3g tlenu
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4Al+3O2----->2Al2O3
15g x
2mAl=4*27u=108u
6mO=6*16u=96u
108u-------15g
96u---------x
x=13,3g tlenu