Oblicz, ile gramów tlenku węgla(II) powstanie po spaleniu 120 gramów kwasu etanowego
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CH₃COOH + O₂ → 2CO + 2H₂O
mCH₃COOH = 60 g/mol
mCO = 28 g/mol
60g CH₃COOH - 2*28 g CO
120g CH₃COOH - x g CO
x= 112 g CO