Oblicz, ile gramów tlenku magnezu powstanie w czasie spalania 120g magnezu.
Oblicz, ile gramów tlenku magnezu powstanie w czasie spalania 120g magnezu.
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mMg=24u
mMgO=40u
2Mg + O2 ---> 2MgO
2*24g Mg ----- 2*40g MgO
120g Mg ------ xg MgO
x = 200g MgO
48u 80u
2Mg + O₂ --> 2MgO
120u x
z proporcji wyliczam x
x = 200g
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