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2Mg+O2=2MgO;
M Mg=24[g/mol];
M O2=32[g/mol];
48[g]Mg reaguje z 32[g]O2;
120[g]Mg - x[g]O2;
x=80[g]O2;
Zgodnie z prawem zachowania masy powstanie;
120[g]+80[g]=200[g]MgO.
Pozdrawiam.....!