oblicz ile gramów stearynianu sodu powstanie w wyniku reakcji 30g wodorotlenku sodu z kwasem stearynowym
C17H35COOH + NaOH ---> C17H35COONa + H2O
M (NaOH)=40 g/mol
M (C17H35COONa)=306 g/mol
40 g NaOH ---daje---> 306 g C17H35COONa
30 g NaOH ---daje---> x g C17H35COONa
x=30*306/40=229,5 g
Powstanie 229,5 g stearynianu sodu.
mNaOH=40u
mC17H35COONa=306u
40g NaOH ------- 306g mydła
30g NaOH ------- xg mydła
x = 229,5g mydła (stearynianu sodu)
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C17H35COOH + NaOH ---> C17H35COONa + H2O
M (NaOH)=40 g/mol
M (C17H35COONa)=306 g/mol
40 g NaOH ---daje---> 306 g C17H35COONa
30 g NaOH ---daje---> x g C17H35COONa
x=30*306/40=229,5 g
Powstanie 229,5 g stearynianu sodu.
mNaOH=40u
mC17H35COONa=306u
C17H35COOH + NaOH ---> C17H35COONa + H2O
40g NaOH ------- 306g mydła
30g NaOH ------- xg mydła
x = 229,5g mydła (stearynianu sodu)