Oblicz , ile gramów soli powstanie w wyniku reakcji zobojętnienia 15,4 g kwasu siarkowego (IV) zasadą sodową.
H₂SO₃ + 2NaOH -> Na₂SO₃ + 2H₂O
MH₂SO₃=2*1g/mol+32g/mol+3*16g/mol=82g/mol
MNa₂SO₃=2*23g/mol+32g/mol+3*16g/mol=126g/mol
82g - 126g
15,4g - xg
x=15,4g*126g:82g=≈23,7g <- tyle gramów soli powstanie
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H₂SO₃ + 2NaOH -> Na₂SO₃ + 2H₂O
MH₂SO₃=2*1g/mol+32g/mol+3*16g/mol=82g/mol
MNa₂SO₃=2*23g/mol+32g/mol+3*16g/mol=126g/mol
82g - 126g
15,4g - xg
x=15,4g*126g:82g=≈23,7g <- tyle gramów soli powstanie