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112g-96g→208g
112g-100%
11,2g-x
x=10%
208g-100%
xg-x%
x=20,8g
Odp: w wyniku reakcji powstanie 20,8g siarczku żelaza
208g Fe2S3 - 112g Fe
x = 208*11,2/112
x = 20,8g Fe2S3