Oblicz ile gramów ołowiu znajduje się w 0.15g antydetonatora o wzorze sumarycznym Pb(C2H5)4
Pb(C₂H₅)₄ - 207u + 8 x 12u +20 x 1u = 323u
207u x
------- = -----
323u 0,15g
x ≈ 0,1g
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Pb(C₂H₅)₄ - 207u + 8 x 12u +20 x 1u = 323u
207u x
------- = -----
323u 0,15g
x ≈ 0,1g
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)