Oblicz ile gramów mydła powstanie w reakcji 35,5 g kwasu stearynowego z 25g 40-procentowego roztworu NaOH
C17H35COOH + NaOH----->C17H35COONa + H2O
25*40%=10gNaOH
40g NaOH reaguje z 284g C17H35COOH
10g NaOH reaguje z Xg C17H35COOH
X=71g
Mamy nadmiar NaOH
35,5g-306 ( M=C17H35COONa)
X-284
X=38,25 g
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C17H35COOH + NaOH----->C17H35COONa + H2O
25*40%=10gNaOH
40g NaOH reaguje z 284g C17H35COOH
10g NaOH reaguje z Xg C17H35COOH
X=71g
Mamy nadmiar NaOH
35,5g-306 ( M=C17H35COONa)
X-284
X=38,25 g