Oblicz ile gramów kwasu siarkowego VI można otrzymać w 20 g kwasu i 40 g wody .
1.SO3 +H2O ----->H2SO480g 98g20g xx=20*98/80=29g2.ms=10gmr=400gszukane Cp?Cp= ms/mr *100%Cp= 10/400 *100%Cp=2,5%3.ms=40gmw=160gmr= ms +mwmr=40+160mr=200gCp= 40/200*100%Cp=20%
ms=20g
mw=40g
mr=ms+mw
mr=60g
Cp=ms*100%/mr
Cp=20*100/60
Cp = 33,33%
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1.SO3 +H2O ----->H2SO4
80g 98g
20g x
x=20*98/80=29g
2.ms=10g
mr=400g
szukane Cp?
Cp= ms/mr *100%
Cp= 10/400 *100%
Cp=2,5%
3.ms=40g
mw=160g
mr= ms +mw
mr=40+160
mr=200g
Cp= 40/200*100%
Cp=20%
ms=20g
mw=40g
mr=ms+mw
mr=60g
Cp=ms*100%/mr
Cp=20*100/60
Cp = 33,33%