Oblicz ile gramów kwasu metanowego użyto do reakcji z magnezem , jeżeli otrzymano 11,4gr. metanianu magnezu.
2HCOOH + Mg -------> (HCOO)2Mg + H2↑
92g HCOOH -------- 114g (HCOO)2Mg
X -------------------- 11,4g (HCOO)2Mg
X=9,2g HCOOH
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2HCOOH + Mg -------> (HCOO)2Mg + H2↑
92g HCOOH -------- 114g (HCOO)2Mg
X -------------------- 11,4g (HCOO)2Mg
X=9,2g HCOOH