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mC₂H₅OH=46u
C₆H₁₂O₆ ---> 2C₂H₅OH + 2CO₂
180g glukozy ---- 2*46g etanolu
xg glukozy ---- 500g etanolu
x = 978,3g glukozy
ms=500g etanolu
n=10,87mola:2=5,435 mola
ms glukoza=5,435 *180g/mol=978,3 g