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0,01=ms/500g
ms=5g MgCl2
500-5=495g wody
495g wody=495cm3 (poniewaz gestosc wody to 1g/cm3)
Cp=1%
ms=?
Cp=ms/mr * 100% /*mr
Cp*mr=ms*100% /:100%
ms=Cp*mr/100%
ms=1%*500g/100%
ms=5g
500g-5g=495g
459g*1g/cm3=495cm3
Odp: Należy przygotować 5g chlorku magnezu i 495 cm3 wody.