Question

Oblicz, ile gramów 20% roztworu kwasu octowego przereaguje z 32,7g cynku.

Plisss na jutro ;(

Answer 1

mZn=65u

mCH3COOH=60u

Zn + 2CH3COOH ---> (CH3COO)2 Zn + H2
65g Zn ------- 120g kwasu

32,7g Zn ------ xg kwasu

x = 60,37g kwasu

 

ms=60,37g

Cp=20%

mr=ms*100%/Cp

mr=60,37*100/20

mr = 301,85g roztworu kwasu