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2Na+2HCl = 2NaCI + H2
m2Na = 2 * 23u = 46u
mH2 = 2 * 1u = 2u
46u Na ------------------ 2u H2
50g Na ---------------- x
x = 50g * 2u / 46u
x = 2,2g
Wydzieli się 2,2 g wodru