oblicz ile gram tlenu trzeba uzyc w reakcji glinu z tlenem aby otrzymac 12g tlenku glinu
4Al + 3O₂ ------> 2Al₂O₃
xg 12g
Masa Al₂O₃ = 27*2+3*16=102g/mol
xg --------- 12g
3*32g ------ 2*102g/mol
x=5,65g
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4Al + 3O₂ ------> 2Al₂O₃
xg 12g
Masa Al₂O₃ = 27*2+3*16=102g/mol
xg --------- 12g
3*32g ------ 2*102g/mol
x=5,65g