oblicz ile (g) potasu i ile (g) wody należy dpdać aby otrzymać 20 (g) wodorotlenku potasu
(g)-gramy
2K + 2H2O ---> 2KOH + H2
M=39g/mol 36g/mol 73g/mol
39g K ---------- 73 g KOH
x ----------- 20g KOH
x=29*3/73=10,68 [g]
36g H2O ------------ 73g KOH
x ----------------- 20g KOH
x= 20*36/73=9,86[g]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
2K + 2H2O ---> 2KOH + H2
M=39g/mol 36g/mol 73g/mol
39g K ---------- 73 g KOH
x ----------- 20g KOH
x=29*3/73=10,68 [g]
36g H2O ------------ 73g KOH
x ----------------- 20g KOH
x= 20*36/73=9,86[g]