Oblicz ile g i dm3 tlenu nalezy uzyc do całkowitego spalania 20g etanu.Gestosc tlenu wynosi 1,43g\dm3
mC2H6=30u
mO=32u
2C2H6 + 7 O2 ---> 4CO2 + 6H2O
2*30g etanu ----- 7*32g tlenu
20g etanu -------- xg tlenu
x = 74,67g tlenu
m=74,67g
d=1,43g/dm3
v=m/d
v=74,67/1,43
v = 52,2dm3 tlenu
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mC2H6=30u
mO=32u
2C2H6 + 7 O2 ---> 4CO2 + 6H2O
2*30g etanu ----- 7*32g tlenu
20g etanu -------- xg tlenu
x = 74,67g tlenu
m=74,67g
d=1,43g/dm3
v=m/d
v=74,67/1,43
v = 52,2dm3 tlenu