Odpowiedź:
[tex]a_n = \frac{2 n^4 - 1}{2 n^4 - n^3 +2 n^2 + 3} = \frac{2 - \frac{1}{n^4} }{2 - \frac{1}{n} + \frac{2}{n^2} + \frac{3}{n^4} }[/tex]
więc
[tex]\lim_{n \to \infty} a_n = \frac{2 - 0}{2 - 0 + 0 + 0} = \frac{2}{2} = 1[/tex]
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Odpowiedź:
[tex]a_n = \frac{2 n^4 - 1}{2 n^4 - n^3 +2 n^2 + 3} = \frac{2 - \frac{1}{n^4} }{2 - \frac{1}{n} + \frac{2}{n^2} + \frac{3}{n^4} }[/tex]
więc
[tex]\lim_{n \to \infty} a_n = \frac{2 - 0}{2 - 0 + 0 + 0} = \frac{2}{2} = 1[/tex]
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Szczegółowe wyjaśnienie: