[tex]\lim_{n \to \infty} \frac{-4n^2+6n-1}{3n+5}= \lim_{n \to \infty} \frac{-4n+6-\frac{1}{n}}{3+\frac{5}{n}}=[\frac{-4*\infty+6-0}{3+0}]=-\infty[/tex]
[tex]\lim_{n \to \infty} \frac{-4n^3+6n^2+4n+1}{-8n^4+6n^2+3}= \lim_{n \to \infty} \frac{-\frac{4}{n}+\frac{6}{n^2}+\frac{4}{n^3}+\frac{1}{n^4}}{-8+\frac{6}{n^2}+\frac{3}{n^4}}=[\frac{0+0+0+0}{-8+0+0}]=0[/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
[tex]\lim_{n \to \infty} \frac{-4n^2+6n-1}{3n+5}= \lim_{n \to \infty} \frac{-4n+6-\frac{1}{n}}{3+\frac{5}{n}}=[\frac{-4*\infty+6-0}{3+0}]=-\infty[/tex]
[tex]\lim_{n \to \infty} \frac{-4n^3+6n^2+4n+1}{-8n^4+6n^2+3}= \lim_{n \to \infty} \frac{-\frac{4}{n}+\frac{6}{n^2}+\frac{4}{n^3}+\frac{1}{n^4}}{-8+\frac{6}{n^2}+\frac{3}{n^4}}=[\frac{0+0+0+0}{-8+0+0}]=0[/tex]