Odpowiedź:
a ) = [tex]\sqrt{6 - 2} = \sqrt{4} = 2[/tex]
b) = [tex]\sqrt{11 + 7 - 2} = \sqrt{16} = 4[/tex]
c ) [tex]\sqrt{169 - 25} = \sqrt{144} = 12[/tex]
d ) = [tex]\sqrt{12 : 5 : 2} = \sqrt{2,4 : 2} = \sqrt{1,2} =\sqrt{\frac{4*3}{10} } = 2*\sqrt{\frac{3}{10} } } =[/tex][tex]\frac{\sqrt{30} }{5}[/tex]
e )
f ) = 4*5 - 2*8 = 20 - 16 = 4
g ) = - 3*( 9 - 10 ) = - 3*(-1) = 3
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Verified answer
Mam nadzieje, że pomogłamOdpowiedź:
a ) = [tex]\sqrt{6 - 2} = \sqrt{4} = 2[/tex]
b) = [tex]\sqrt{11 + 7 - 2} = \sqrt{16} = 4[/tex]
c ) [tex]\sqrt{169 - 25} = \sqrt{144} = 12[/tex]
d ) = [tex]\sqrt{12 : 5 : 2} = \sqrt{2,4 : 2} = \sqrt{1,2} =\sqrt{\frac{4*3}{10} } = 2*\sqrt{\frac{3}{10} } } =[/tex][tex]\frac{\sqrt{30} }{5}[/tex]
e )
f ) = 4*5 - 2*8 = 20 - 16 = 4
g ) = - 3*( 9 - 10 ) = - 3*(-1) = 3
Szczegółowe wyjaśnienie: