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m-masa szklanki z woda=0,3kg
S-pole podstawy=35cm²=0,0035m²
N/cm²=10000Pa
Szukane:
p=?
Rozwiazanie:
F=mg
F=0,3*10=3N
p=F/s
p=3:0,0035
p=857,14Pa
Cisnienie pod szklanka to 857,14Pa