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M H2SO3 = 2*1u + 32u + 3*16u = 2u + 32u +48u = 82u
%S = 32u/82u * 100%= 3200/82% = 39,02%
b)stosunek masowy pierwiastków w kwasie siarkowym (IV)
M H 2*1u 2 1
----- ----- ----- ----
M S = 32u = 32 = 16
----- ----- ----- -----
M O 3*16u 48 24
c)stosunek masowy pierwiastków w tlenku siarki (IV)
M S 32u 32 1
---- = ----- = ----- = -----
M O 2*16u 32 1