oblicz :
a)
b)
a) Al glin
b) N2O3
mE₂O₃ = 102u
2E + 3*16u = 102u
2E= 102u - 48u
2E= 54u /:2
E= 27u = masa glinu (Al)
E₂O₃= Al₂O₃
m N₂Ox = 76u
2*14u + 16X = 76u
16u X= 76u - 28u
16u X = 48u /:16u
X= 3
N₂Ox =N₂O₃
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a) Al glin
b) N2O3
a)
mE₂O₃ = 102u
2E + 3*16u = 102u
2E= 102u - 48u
2E= 54u /:2
E= 27u = masa glinu (Al)
E₂O₃= Al₂O₃
b)
m N₂Ox = 76u
2*14u + 16X = 76u
16u X= 76u - 28u
16u X = 48u /:16u
X= 3
N₂Ox =N₂O₃