Obilicz ile:
a)dm{3}tlenu
b)dm{3} powietrza
c)gramów tlenu
d)gramów powietrza
Potzeba do spalenia całkowitego 300g etanu
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a)
300g x
2C₂H₆ + 7O₂ ---> 4CO₂ + 6H₂O
60g 156,8dm³
x=300g·156,8dm³/60g=784dm³
b)
784dm³ - 21%
y - 100%
y=784dm³·100%/21%≈3733,3dm³
c)
300g a
2C₂H₆ + 7O₂ ---> 4CO₂ + 6H₂O
60g 224g
a=300g·224g/60g=1120g
d)
1120g - 21%
b - 100%
b=1120g·100%/21%≈5333,3g