Question

Nyatakan persamaan berikut dalam bentuk umum persamaan kuadrat dan tentukan nilai a,b,c,
a) (x-2) (x+1) = 2(x-3)
b) ( x-1 )^2 - 2(x+3) - 2=0
bantuannya ya teman teman :D

Answer 1

A) (x - 2)(x + 1) = 2(x - 3)
x² - 2x + x - 2 = 2x - 6
x² - x - 2 = 2x - 6
x² - x - 2x - 2 + 6 = 0
x² - 3x + 4 = 0
(x - 4)(x + 1) = 0
x = 4 atau x = -1

b) (x - 1)² - 2(x + 3) - 2 = 0
x² - 2x + 1 - 2x - 6 - 2 = 0
x² - 4x - 7 = 0
x² - 4x + 4 - 11 = 0
x² - 4x + 4 = 11
(x - 2)² = 11
x - 2 = 11
x = 11 + 2 = 13
atau
x - 2 = -11
x = 2 - 11 = (-9)