Question

nyatakan kebentuk paling sederhana dalam pangkat positif!!!​

Answer 1

Materi : Bentuk Akar dan Pangkat

Bagian A

( x-¹ - y-³ )/( x-⁵ + y-² )

= ( 1/x - 1/y³ )/( 1/x⁵ + 1/y² )

= ( y³ - x )/xy³ ÷ ( x⁵ + y² )/x⁵y²

= ( y³ - x )/xy³ . x⁵y²/( x⁵ + y² )

= ( y³ - x )/( x⁵ + y² ) . x⁵y²/xy³

= ( y³ - x )/( x⁵ + y² ) . x⁴/y

= ( x⁴y³ - x⁵ )/( x⁵y + y³ )

Bagian B

( xy-² + x-³y )/( x²y-¹ - x-⁴y³ )

= ( x/y² + y/x³ )/( x²/y - y³/x⁴ )

= ( x⁴ + y³ )/x³y² ÷ ( x⁶ - y⁴ )/x⁴y

= ( x⁴ + y³ )/( x⁶ - y⁴ ) . x³y²/x⁴y

= ( x⁴ + y³ )/( x⁶ - y⁴ ) . y/x

= ( x⁴y + y⁴ )/( x⁷ - xy⁴ )

Semoga bisa membantu

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