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tinggi = 16
Kel alas = π * d
75,36 = 3,14 * d
d = 75,36 /3,14 = 24
d = 24 ; r = 12
pitagoras untuk mencari tinggi selimut
r² + t²
12²+16² = 144 + 256 = 400
tinggi selimut = √400 =20
luas selimut = 1/2 * tinggi selimut * keliling alas
= 1/2 * 20 * 75,36 = 753,6
kl. alas = 75,36cm
kl.alas/k. lingkaran= 2.phi.r
75,36cm = 2.3,14.r
75,36 = 6,28.r
75,36 =r
6,28
12 = r
s=t+r
s=16+12
s=256+144
s=400
s=20
l.selimut kerucut= phi.r.s.
=3,1412.20
=753,6