Penjelasan dengan langkah-langkah:
Bagan soal nomer 4
a) (Lemparan pertama, Lemparan kedua)
(1, 1), (1, 2), (1, 3), (1, 4)
(2, 1), (2, 2), (2, 3), (2, 4)
(3, 1), (3, 2), (3, 3), (3, 4)
(4, 1), (4, 2), (4, 3), (4, 4)
b) n(Kemungkinan) = 16
Nomer 6
a) perbedaan 3 = (1, 4) dan (4, 1)
n(s.3) = 2
n(2 dadu pertama) = 4 yaitu (2, 1), (2, 2), (2, 3), (2, 4)
P(s.3 atau 2) = 2+4 = 6 = ⅜
16 16
b) n(s.2) = 4
n(kembar) = 4
P(s.2 atau kembar) = 4 + 4 = 8 = ½
c) n(s.0) = 4
d) n(s.0) = 4
n(jumlah 6) = 0
P(s.2 atau kembar) = 4 + 0 = 4 = ¼
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Penjelasan dengan langkah-langkah:
Bagan soal nomer 4
a) (Lemparan pertama, Lemparan kedua)
(1, 1), (1, 2), (1, 3), (1, 4)
(2, 1), (2, 2), (2, 3), (2, 4)
(3, 1), (3, 2), (3, 3), (3, 4)
(4, 1), (4, 2), (4, 3), (4, 4)
b) n(Kemungkinan) = 16
Nomer 6
a) perbedaan 3 = (1, 4) dan (4, 1)
n(s.3) = 2
n(2 dadu pertama) = 4 yaitu (2, 1), (2, 2), (2, 3), (2, 4)
P(s.3 atau 2) = 2+4 = 6 = ⅜
16 16
b) n(s.2) = 4
n(kembar) = 4
P(s.2 atau kembar) = 4 + 4 = 8 = ½
16 16
c) n(s.0) = 4
n(kembar) = 4
P(s.2 atau kembar) = 4 + 4 = 8 = ½
16 16
d) n(s.0) = 4
n(jumlah 6) = 0
P(s.2 atau kembar) = 4 + 0 = 4 = ¼
16 16