Nomor 40... bingung pake rumus apa .... Question from @adronny

October 2018 2 20 Report

Nomor 40... bingung pake rumus apa ...

FadlyHermaja $E_1=\frac{m*c^2}{\sqrt{1-(\frac{v_1}{c})^2}} \\ \\ E_1=\frac{m*c^2}{\sqrt{1-(\frac{0,6c}{c})^2}} \\ \\ E_1=\frac{m*c^2}{\sqrt{1-0,36}} \\ \\ E_1=\frac{m*c^2}{\sqrt{0,64}} \\ \\ E_1=\frac{m*c^2}{0,8} \\ \\ E_1=1,25*m*c^2$

$E_2=\frac{m*c^2}{\sqrt{1-(\frac{v_2}{c})^2}} \\ \\ E_2=\frac{m*c^2}{\sqrt{1-(\frac{\frac{\sqrt{3}}{2}c}{c})^2}} \\ \\ E_2=\frac{m*c^2}{\sqrt{1-\frac{3}{4}}} \\ \\ E_2=\frac{m*c^2}{\sqrt{\frac{1}{4}}} \\ \\ E_2=\frac{m*c^2}{0,5} \\ \\ E_2=2*m*c^2$

Selisih energinya adalah = 0,75 m c²
Jawaban D

0 votes Thanks 2

ryanriyadiii Enaknya rumusnya dijadiin invers trigononya aja ..

E= moc^2 / inv 0.6 jdi 0.8
e=1.25 moc^2
E= moc^2 / inv sqrt3 /2 jdi 1/2
e= 2moc^2
hdi dE= 0.75moc^2 ..

0 votes Thanks 1

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