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perbandingan mol = perbandingan koefisien
K₂Cr₂O₇ + 14 HCl ⇒ 2 KCl + 2 CrCl₃ + 3 Cl₂ + 7 H₂O
0,5 mol 7 mol 1,5 mol
mol HCl yang dibutuhkan 7 mol
Volume gas Cl₂ = 22,4 x 1,5 = 33,6 liter