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m 0,16 0,16
b 0,16 0,16 0,16
s - - 0,16
M NH4Cl = 0,16 ÷ 0,4 = 0,4
terbentuk garam yang bersifat asam ⇒ NH4Cl
[H^+] = √(Kw ÷ Kb) × (M)
= √(10^-14 ÷ 10^-5) × ( 0,4)
= √ 4 × 10^-10 = 2 × 10^-5
pH = 5 - log 2