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y-y1/y2-y1=x-x1/x2-x1
y-(-2)/1-(-2) = x-3/4-3
y+2/3=x-3/1
(y+2).1 = 3(x-3)
y+2 = 3x-9
y = 3x -9-2
y=3x-11
A(6,a)
x=6 , y = ....?
y= 3.6 -11 = 18-11 = 7 (D)
18.(3,-5) , (-1,-3)
m grs k = -3 - (-5) / -1-3
=-3+5/-4
=-2/4 = -1/2
syarat tegak lurus :
m1.m2=-1
-1/2. m2 = -1
m2= 2
a. m= 2
b. m= -2
c. m= 1/2
d. m= -1/2
jd yg tegak lurus dgn k adalah
a. 2x -y = 6