kel = 2(p+l) 36 = 2(3x-4 + x+2) 36/2= 4x-2 18 = 4x-2 18+2 = 4x 20/4 = x 5 = x
maka, p = 3x-4 = 3*5 - 4 = 15-4 = 11 l = x+2 = 5+2 = 7 (C)
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13) P = 3x-4 L = x+2 keliling = 2(P+L) 36 = 2(3x-4+x+2) 36 = 2(4x-2) 36 = 8x-4 8x = 36+4 8x = 40 x = 5 maka lebar = 5+2 = 7 meter (C)
19) titik melalui K(-2,10) dan L(1,1) m = (y₂-y₁)/(x₂-x₁) = (1-10)/(1-(-2)) = -9/3 = -3 apabila titik berada pada garis maka gradiennya sama ambil titik A(3,y) dan K(-2,10) m = (y₂-y₁)/(x₂-x₁) -3 = (10-y)/(-2-3) -3 = (10-y)/-5 10-y = 15 y = 10-15 y = -5 (B)
20) harga sebuah jaket dan 3 topi = j+3t 4j+5t = 600.000 3j+2t = 380.000 _ j+3t = 220.000 (A)
l = x+2
kel = 36
kel = 2(p+l)
36 = 2(3x-4 + x+2)
36/2= 4x-2
18 = 4x-2
18+2 = 4x
20/4 = x
5 = x
maka, p = 3x-4 = 3*5 - 4 = 15-4 = 11
l = x+2 = 5+2 = 7 (C)
L = x+2
keliling = 2(P+L)
36 = 2(3x-4+x+2)
36 = 2(4x-2)
36 = 8x-4
8x = 36+4
8x = 40
x = 5
maka lebar = 5+2 = 7 meter (C)
19) titik melalui K(-2,10) dan L(1,1)
m = (y₂-y₁)/(x₂-x₁) = (1-10)/(1-(-2)) = -9/3 = -3
apabila titik berada pada garis maka gradiennya sama
ambil titik A(3,y) dan K(-2,10)
m = (y₂-y₁)/(x₂-x₁)
-3 = (10-y)/(-2-3)
-3 = (10-y)/-5
10-y = 15
y = 10-15
y = -5 (B)
20) harga sebuah jaket dan 3 topi = j+3t
4j+5t = 600.000
3j+2t = 380.000 _
j+3t = 220.000 (A)