Question

Nomor 126 tolong dijawab

Answer 1

C :H :O=%C/ArC: %H/ArH: %O/ArO
=60/12: 4,48/1: 35,5/16
=5mol: 4,48mol: 2,2 mol

rumus empiris=C5H4O2

rumus molekul:

Mr(C5H4O2)n=Mr senyawa
[12(5)+4+16(2)]n=180
[60+4+32]n=180
96n=180
n=2

Jadi rumus molekulnya=C10H8O4